[CCCure CISSP] Access Control - Brute Force Attack

[Hai Tiet Kim]

Hi,

If the correct answer is B then we will understand the question as follows:

"If the password is made up of *A MAXIMUM* of 4 numeric characters, how many
attempts
    needed for a successful brute force attack?"

So we will have 10^4 + 10^3 + 10^2 + 10^1 = 11110 choices.

Best regards,
Hai

On Mon, Feb 15, 2010 at 12:05 AM, Nimal Gunarathna <ng949 at yahoo.com> wrote:

> Hello Everyone, I have a question for you all?
>
> 1. If the password is made up of 4 numeric characters, how many attempts
>     needed for a successful brute force attack?
>
> A. 10000
> B. 11110
> C. 1024
> D. 11100
>
> *What I think: *
> Every numeric character has 10 choices. Then 4 characters 10^4 = 10000
> choices and
> the answer should be A.  But the right answer is B. How is that possible?
>
>
>
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>
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